Optimal. Leaf size=231 \[ \frac {17 \sqrt {x^4+3 x^2+2} x}{9800 \left (5 x^2+7\right )}-\frac {3 \sqrt {x^4+3 x^2+2} x}{350 \left (5 x^2+7\right )^2}+\frac {3 \left (x^2+2\right ) x}{392 \sqrt {x^4+3 x^2+2}}+\frac {5 \left (x^2+1\right ) \sqrt {\frac {x^2+2}{2 x^2+2}} F\left (\tan ^{-1}(x)|\frac {1}{2}\right )}{784 \sqrt {x^4+3 x^2+2}}-\frac {3 \left (x^2+1\right ) \sqrt {\frac {x^2+2}{2 x^2+2}} E\left (\tan ^{-1}(x)|\frac {1}{2}\right )}{196 \sqrt {x^4+3 x^2+2}}+\frac {141 \left (x^2+2\right ) \Pi \left (\frac {2}{7};\tan ^{-1}(x)|\frac {1}{2}\right )}{27440 \sqrt {2} \sqrt {\frac {x^2+2}{x^2+1}} \sqrt {x^4+3 x^2+2}} \]
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Rubi [A] time = 0.67, antiderivative size = 288, normalized size of antiderivative = 1.25, number of steps used = 27, number of rules used = 10, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.417, Rules used = {1228, 1099, 1135, 1223, 1696, 1716, 1189, 1214, 1456, 539} \[ \frac {17 \sqrt {x^4+3 x^2+2} x}{9800 \left (5 x^2+7\right )}-\frac {3 \sqrt {x^4+3 x^2+2} x}{350 \left (5 x^2+7\right )^2}+\frac {3 \left (x^2+2\right ) x}{392 \sqrt {x^4+3 x^2+2}}+\frac {5 \left (x^2+1\right ) \sqrt {\frac {x^2+2}{x^2+1}} F\left (\tan ^{-1}(x)|\frac {1}{2}\right )}{784 \sqrt {2} \sqrt {x^4+3 x^2+2}}-\frac {6 \sqrt {2} \left (x^2+1\right ) \sqrt {\frac {x^2+2}{x^2+1}} E\left (\tan ^{-1}(x)|\frac {1}{2}\right )}{875 \sqrt {x^4+3 x^2+2}}-\frac {39 \left (x^2+1\right ) \sqrt {\frac {x^2+2}{x^2+1}} E\left (\tan ^{-1}(x)|\frac {1}{2}\right )}{24500 \sqrt {2} \sqrt {x^4+3 x^2+2}}+\frac {141 \left (x^2+2\right ) \Pi \left (\frac {2}{7};\tan ^{-1}(x)|\frac {1}{2}\right )}{27440 \sqrt {2} \sqrt {\frac {x^2+2}{x^2+1}} \sqrt {x^4+3 x^2+2}} \]
Antiderivative was successfully verified.
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Rule 539
Rule 1099
Rule 1135
Rule 1189
Rule 1214
Rule 1223
Rule 1228
Rule 1456
Rule 1696
Rule 1716
Rubi steps
\begin {align*} \int \frac {\left (2+3 x^2+x^4\right )^{3/2}}{\left (7+5 x^2\right )^3} \, dx &=\int \left (\frac {9}{625 \sqrt {2+3 x^2+x^4}}+\frac {x^2}{125 \sqrt {2+3 x^2+x^4}}+\frac {36}{625 \left (7+5 x^2\right )^3 \sqrt {2+3 x^2+x^4}}-\frac {12}{625 \left (7+5 x^2\right )^2 \sqrt {2+3 x^2+x^4}}-\frac {11}{625 \left (7+5 x^2\right ) \sqrt {2+3 x^2+x^4}}\right ) \, dx\\ &=\frac {1}{125} \int \frac {x^2}{\sqrt {2+3 x^2+x^4}} \, dx+\frac {9}{625} \int \frac {1}{\sqrt {2+3 x^2+x^4}} \, dx-\frac {11}{625} \int \frac {1}{\left (7+5 x^2\right ) \sqrt {2+3 x^2+x^4}} \, dx-\frac {12}{625} \int \frac {1}{\left (7+5 x^2\right )^2 \sqrt {2+3 x^2+x^4}} \, dx+\frac {36}{625} \int \frac {1}{\left (7+5 x^2\right )^3 \sqrt {2+3 x^2+x^4}} \, dx\\ &=\frac {x \left (2+x^2\right )}{125 \sqrt {2+3 x^2+x^4}}-\frac {3 x \sqrt {2+3 x^2+x^4}}{350 \left (7+5 x^2\right )^2}+\frac {x \sqrt {2+3 x^2+x^4}}{175 \left (7+5 x^2\right )}-\frac {\sqrt {2} \left (1+x^2\right ) \sqrt {\frac {2+x^2}{1+x^2}} E\left (\tan ^{-1}(x)|\frac {1}{2}\right )}{125 \sqrt {2+3 x^2+x^4}}+\frac {9 \left (1+x^2\right ) \sqrt {\frac {2+x^2}{1+x^2}} F\left (\tan ^{-1}(x)|\frac {1}{2}\right )}{625 \sqrt {2} \sqrt {2+3 x^2+x^4}}-\frac {\int \frac {62+70 x^2+25 x^4}{\left (7+5 x^2\right ) \sqrt {2+3 x^2+x^4}} \, dx}{4375}+\frac {3 \int \frac {74-10 x^2-25 x^4}{\left (7+5 x^2\right )^2 \sqrt {2+3 x^2+x^4}} \, dx}{8750}-\frac {11 \int \frac {1}{\sqrt {2+3 x^2+x^4}} \, dx}{1250}+\frac {11}{500} \int \frac {2+2 x^2}{\left (7+5 x^2\right ) \sqrt {2+3 x^2+x^4}} \, dx\\ &=\frac {x \left (2+x^2\right )}{125 \sqrt {2+3 x^2+x^4}}-\frac {3 x \sqrt {2+3 x^2+x^4}}{350 \left (7+5 x^2\right )^2}+\frac {17 x \sqrt {2+3 x^2+x^4}}{9800 \left (7+5 x^2\right )}-\frac {\sqrt {2} \left (1+x^2\right ) \sqrt {\frac {2+x^2}{1+x^2}} E\left (\tan ^{-1}(x)|\frac {1}{2}\right )}{125 \sqrt {2+3 x^2+x^4}}+\frac {7 \left (1+x^2\right ) \sqrt {\frac {2+x^2}{1+x^2}} F\left (\tan ^{-1}(x)|\frac {1}{2}\right )}{1250 \sqrt {2} \sqrt {2+3 x^2+x^4}}+\frac {\int \frac {2838+2310 x^2+975 x^4}{\left (7+5 x^2\right ) \sqrt {2+3 x^2+x^4}} \, dx}{245000}+\frac {\int \frac {-175-125 x^2}{\sqrt {2+3 x^2+x^4}} \, dx}{109375}-\frac {13 \int \frac {1}{\left (7+5 x^2\right ) \sqrt {2+3 x^2+x^4}} \, dx}{4375}+\frac {\left (11 \sqrt {1+\frac {x^2}{2}} \sqrt {2+2 x^2}\right ) \int \frac {\sqrt {2+2 x^2}}{\sqrt {1+\frac {x^2}{2}} \left (7+5 x^2\right )} \, dx}{500 \sqrt {2+3 x^2+x^4}}\\ &=\frac {x \left (2+x^2\right )}{125 \sqrt {2+3 x^2+x^4}}-\frac {3 x \sqrt {2+3 x^2+x^4}}{350 \left (7+5 x^2\right )^2}+\frac {17 x \sqrt {2+3 x^2+x^4}}{9800 \left (7+5 x^2\right )}-\frac {\sqrt {2} \left (1+x^2\right ) \sqrt {\frac {2+x^2}{1+x^2}} E\left (\tan ^{-1}(x)|\frac {1}{2}\right )}{125 \sqrt {2+3 x^2+x^4}}+\frac {7 \left (1+x^2\right ) \sqrt {\frac {2+x^2}{1+x^2}} F\left (\tan ^{-1}(x)|\frac {1}{2}\right )}{1250 \sqrt {2} \sqrt {2+3 x^2+x^4}}+\frac {11 \left (2+x^2\right ) \Pi \left (\frac {2}{7};\tan ^{-1}(x)|\frac {1}{2}\right )}{1750 \sqrt {2} \sqrt {\frac {2+x^2}{1+x^2}} \sqrt {2+3 x^2+x^4}}-\frac {\int \frac {-4725-4875 x^2}{\sqrt {2+3 x^2+x^4}} \, dx}{6125000}-\frac {1}{875} \int \frac {x^2}{\sqrt {2+3 x^2+x^4}} \, dx-\frac {13 \int \frac {1}{\sqrt {2+3 x^2+x^4}} \, dx}{8750}-\frac {1}{625} \int \frac {1}{\sqrt {2+3 x^2+x^4}} \, dx+\frac {13 \int \frac {2+2 x^2}{\left (7+5 x^2\right ) \sqrt {2+3 x^2+x^4}} \, dx}{3500}+\frac {303 \int \frac {1}{\left (7+5 x^2\right ) \sqrt {2+3 x^2+x^4}} \, dx}{49000}\\ &=\frac {6 x \left (2+x^2\right )}{875 \sqrt {2+3 x^2+x^4}}-\frac {3 x \sqrt {2+3 x^2+x^4}}{350 \left (7+5 x^2\right )^2}+\frac {17 x \sqrt {2+3 x^2+x^4}}{9800 \left (7+5 x^2\right )}-\frac {6 \sqrt {2} \left (1+x^2\right ) \sqrt {\frac {2+x^2}{1+x^2}} E\left (\tan ^{-1}(x)|\frac {1}{2}\right )}{875 \sqrt {2+3 x^2+x^4}}+\frac {11 \left (1+x^2\right ) \sqrt {\frac {2+x^2}{1+x^2}} F\left (\tan ^{-1}(x)|\frac {1}{2}\right )}{4375 \sqrt {2} \sqrt {2+3 x^2+x^4}}+\frac {11 \left (2+x^2\right ) \Pi \left (\frac {2}{7};\tan ^{-1}(x)|\frac {1}{2}\right )}{1750 \sqrt {2} \sqrt {\frac {2+x^2}{1+x^2}} \sqrt {2+3 x^2+x^4}}+\frac {27 \int \frac {1}{\sqrt {2+3 x^2+x^4}} \, dx}{35000}+\frac {39 \int \frac {x^2}{\sqrt {2+3 x^2+x^4}} \, dx}{49000}+\frac {303 \int \frac {1}{\sqrt {2+3 x^2+x^4}} \, dx}{98000}-\frac {303 \int \frac {2+2 x^2}{\left (7+5 x^2\right ) \sqrt {2+3 x^2+x^4}} \, dx}{39200}+\frac {\left (13 \sqrt {1+\frac {x^2}{2}} \sqrt {2+2 x^2}\right ) \int \frac {\sqrt {2+2 x^2}}{\sqrt {1+\frac {x^2}{2}} \left (7+5 x^2\right )} \, dx}{3500 \sqrt {2+3 x^2+x^4}}\\ &=\frac {3 x \left (2+x^2\right )}{392 \sqrt {2+3 x^2+x^4}}-\frac {3 x \sqrt {2+3 x^2+x^4}}{350 \left (7+5 x^2\right )^2}+\frac {17 x \sqrt {2+3 x^2+x^4}}{9800 \left (7+5 x^2\right )}-\frac {39 \left (1+x^2\right ) \sqrt {\frac {2+x^2}{1+x^2}} E\left (\tan ^{-1}(x)|\frac {1}{2}\right )}{24500 \sqrt {2} \sqrt {2+3 x^2+x^4}}-\frac {6 \sqrt {2} \left (1+x^2\right ) \sqrt {\frac {2+x^2}{1+x^2}} E\left (\tan ^{-1}(x)|\frac {1}{2}\right )}{875 \sqrt {2+3 x^2+x^4}}+\frac {5 \left (1+x^2\right ) \sqrt {\frac {2+x^2}{1+x^2}} F\left (\tan ^{-1}(x)|\frac {1}{2}\right )}{784 \sqrt {2} \sqrt {2+3 x^2+x^4}}+\frac {9 \left (2+x^2\right ) \Pi \left (\frac {2}{7};\tan ^{-1}(x)|\frac {1}{2}\right )}{1225 \sqrt {2} \sqrt {\frac {2+x^2}{1+x^2}} \sqrt {2+3 x^2+x^4}}-\frac {\left (303 \sqrt {1+\frac {x^2}{2}} \sqrt {2+2 x^2}\right ) \int \frac {\sqrt {2+2 x^2}}{\sqrt {1+\frac {x^2}{2}} \left (7+5 x^2\right )} \, dx}{39200 \sqrt {2+3 x^2+x^4}}\\ &=\frac {3 x \left (2+x^2\right )}{392 \sqrt {2+3 x^2+x^4}}-\frac {3 x \sqrt {2+3 x^2+x^4}}{350 \left (7+5 x^2\right )^2}+\frac {17 x \sqrt {2+3 x^2+x^4}}{9800 \left (7+5 x^2\right )}-\frac {39 \left (1+x^2\right ) \sqrt {\frac {2+x^2}{1+x^2}} E\left (\tan ^{-1}(x)|\frac {1}{2}\right )}{24500 \sqrt {2} \sqrt {2+3 x^2+x^4}}-\frac {6 \sqrt {2} \left (1+x^2\right ) \sqrt {\frac {2+x^2}{1+x^2}} E\left (\tan ^{-1}(x)|\frac {1}{2}\right )}{875 \sqrt {2+3 x^2+x^4}}+\frac {5 \left (1+x^2\right ) \sqrt {\frac {2+x^2}{1+x^2}} F\left (\tan ^{-1}(x)|\frac {1}{2}\right )}{784 \sqrt {2} \sqrt {2+3 x^2+x^4}}+\frac {141 \left (2+x^2\right ) \Pi \left (\frac {2}{7};\tan ^{-1}(x)|\frac {1}{2}\right )}{27440 \sqrt {2} \sqrt {\frac {2+x^2}{1+x^2}} \sqrt {2+3 x^2+x^4}}\\ \end {align*}
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Mathematica [C] time = 0.38, size = 174, normalized size = 0.75 \[ \frac {-406 i \sqrt {x^2+1} \sqrt {x^2+2} F\left (\left .i \sinh ^{-1}\left (\frac {x}{\sqrt {2}}\right )\right |2\right )-525 i \sqrt {x^2+1} \sqrt {x^2+2} E\left (\left .i \sinh ^{-1}\left (\frac {x}{\sqrt {2}}\right )\right |2\right )+141 i \sqrt {x^2+1} \sqrt {x^2+2} \Pi \left (\frac {10}{7};\left .i \sinh ^{-1}\left (\frac {x}{\sqrt {2}}\right )\right |2\right )+\frac {119 x \left (x^4+3 x^2+2\right )}{5 x^2+7}-\frac {588 x \left (x^4+3 x^2+2\right )}{\left (5 x^2+7\right )^2}}{68600 \sqrt {x^4+3 x^2+2}} \]
Antiderivative was successfully verified.
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fricas [F] time = 0.51, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {{\left (x^{4} + 3 \, x^{2} + 2\right )}^{\frac {3}{2}}}{125 \, x^{6} + 525 \, x^{4} + 735 \, x^{2} + 343}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (x^{4} + 3 \, x^{2} + 2\right )}^{\frac {3}{2}}}{{\left (5 \, x^{2} + 7\right )}^{3}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 0.02, size = 186, normalized size = 0.81 \[ -\frac {3 \sqrt {x^{4}+3 x^{2}+2}\, x}{350 \left (5 x^{2}+7\right )^{2}}+\frac {17 \sqrt {x^{4}+3 x^{2}+2}\, x}{9800 \left (5 x^{2}+7\right )}-\frac {3 i \sqrt {2}\, \sqrt {2 x^{2}+4}\, \sqrt {x^{2}+1}\, \EllipticE \left (\frac {i \sqrt {2}\, x}{2}, \sqrt {2}\right )}{784 \sqrt {x^{4}+3 x^{2}+2}}-\frac {29 i \sqrt {2}\, \sqrt {2 x^{2}+4}\, \sqrt {x^{2}+1}\, \EllipticF \left (\frac {i \sqrt {2}\, x}{2}, \sqrt {2}\right )}{9800 \sqrt {x^{4}+3 x^{2}+2}}+\frac {141 i \sqrt {2}\, \sqrt {\frac {x^{2}}{2}+1}\, \sqrt {x^{2}+1}\, \EllipticPi \left (\frac {i \sqrt {2}\, x}{2}, \frac {10}{7}, \sqrt {2}\right )}{68600 \sqrt {x^{4}+3 x^{2}+2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (x^{4} + 3 \, x^{2} + 2\right )}^{\frac {3}{2}}}{{\left (5 \, x^{2} + 7\right )}^{3}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {{\left (x^4+3\,x^2+2\right )}^{3/2}}{{\left (5\,x^2+7\right )}^3} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (\left (x^{2} + 1\right ) \left (x^{2} + 2\right )\right )^{\frac {3}{2}}}{\left (5 x^{2} + 7\right )^{3}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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